词条 | Orthoptic (geometry) |
释义 |
In the geometry of curves, an orthoptic is the set of points for which two tangents of a given curve meet at a right angle. Examples:
(see below). Generalizations:
Orthoptic of a parabolaAny parabola can be transformed by a rigid motion (angles are not changed) into a parabola with equation . The slope at a point of the parabola is . Replacing gives the parametric representation of the parabola with the tangent slope as parameter: The tangent has the equation with the still unknown , which can be determined by inserting the coordinates of the parabola point. One gets If a tangent contains the point {{math|(x0, y0)}}, off the parabola, then the equation holds, which has two solutions {{math|m1}} and {{math|m2}} corresponding to the two tangents passing {{math|(x0, y0)}}. The free term of a reduced quadratic equation is always the product of its solutions. Hence, if the tangents meet at {{math|(x0, y0)}} orthogonally, the following equations hold: The last equation is equivalent to which is the equation of the directrix. Orthoptic of an ellipse and hyperbolaEllipse{{main|Director circle}}Let be the ellipse of consideration. (1) The tangents of ellipse at neighbored vertices intersect at one of the 4 points , which lie on the desired orthoptic curve (circle ). (2) The tangent at a point of the ellipse has the equation (s. Ellipse). If the point is not a vertex this equation can be solved:Using the abbreviations and the equation one gets: Hence and the equation of a non vertical tangent is Solving relations for and respecting leads to the slope depending parametric representation of the ellipse: (For an other proof: see Ellipse.) If a tangent contains the point , off the ellipse, then the equation holds. Eliminating the square root leads to which has two solutions corresponding to the two tangents passing . The free term of a reduced quadratic equation is always the product of its solutions. Hence, if the tangents meet at orthogonally, the following equations hold: The last equation is equivalent to From (1) and (2) one gets:
HyperbolaThe ellipse case can be adopted nearly exactly to the hyperbola case. The only changes to be made are to replace with and to restrict {{mvar|m}} to {{math|{{abs|m}} > {{sfrac|b|a}}}}. Therefore:
Orthoptic of an astroidAn astroid can be described by the parametric representation . From the condition one recognizes the distance {{mvar|α}} in parameter space at which an orthogonal tangent to {{math|{{vec|ċ}}(t)}} appears. It turns out that the distance is independent of parameter {{mvar|t}}, namely {{math|α {{=}} ± {{sfrac|π|2}}}}. The equations of the (orthogonal) tangents at the points {{math|{{vec|c}}(t)}} and {{math|{{vec|c}}(t + {{sfrac|π|2}})}} are respectively: Their common point has coordinates: This is simultaneously a parametric representation of the orthoptic. Elimination of the parameter {{mvar|t}} yields the implicit representation Introducing the new parameter {{math|φ {{=}} t − {{sfrac|5π|4}}}} one gets (The proof uses the angle sum and difference identities.) Hence we get the polar representation of the orthoptic. Hence:
Isoptic of a parabola, an ellipse and a hyperbolaBelow the isotopics for angles {{math|α ≠ 90°}} are listed. They are called {{mvar|α}}-isoptics. For the proofs see below. Equations of the isoptics
The {{mvar|α}}-isoptics of the parabola with equation {{math|y {{=}} ax2}} are the branches of the hyperbola The branches of the hyperbola provide the isoptics for the two angles {{mvar|α}} and {{mvar|180° − α}} (see picture).
The {{mvar|α}}-isoptics of the ellipse with equation {{math|{{sfrac|x2|a2}} + {{sfrac|y2|b2}} {{=}} 1}} are the two parts of the degree-4 curve (see picture).
The {{mvar|α}}-isoptics of the hyperbola with the equation {{math|{{sfrac|x2|a2}} − {{sfrac|y2|b2}} {{=}} 1}} are the two parts of the degree-4 curve Proofs
A parabola {{math|y {{=}} ax2}} can be parametrized by the slope of its tangents {{math|m {{=}} 2ax}}: The tangent with slope {{mvar|m}} has the equation The point {{math|(x0, y0)}} is on the tangent if and only if This means the slopes {{math|m1}}, {{math|m2}} of the two tangents containing {{math|(x0, y0)}} fulfil the quadratic equation If the tangents meet at angle {{mvar|α}} or {{math|180° − α}}, the equation must be fulfilled. Solving the quadratic equation for {{mvar|m}}, and inserting {{math|m1}}, {{math|m2}} into the last equation, one gets This is the equation of the hyperbola above. Its branches bear the two isoptics of the parabola for the two angles {{mvar|α}} and {{math|180° − α}}.
In the case of an ellipse {{math|{{sfrac|x2|a2}} + {{sfrac|y2|b2}} {{=}} 1}} one can adopt the idea for the orthoptic for the quadratic equation Now, as in the case of a parabola, the quadratic equation has to be solved and the two solutions {{math|m1}}, {{math|m2}} must be inserted into the equation Rearranging shows that the isoptics are parts of the degree-4 curve:
The solution for the case of a hyperbola can be adopted from the ellipse case by replacing {{math|b2}} with {{math|−b2}} (as in the case of the orthoptics, see above). To visualize the isoptics, see implicit curve. External links{{commons category|Isoptics}}
NotesReferences
1 : Curves |
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