| 词条 | 1852 United States presidential election in Iowa |
| 释义 |
| election_name = United States presidential election in Iowa, 1852 | country = Iowa | flag_year = 1852 | type = presidential | ongoing = no | previous_election = United States presidential election in Iowa, 1848 | previous_year = 1848 | next_election = United States presidential election in Iowa, 1856 | next_year = 1856 | election_date = November 2, 1852 | image1 = | nominee1 = Franklin Pierce | party1 = Democratic Party (United States) | home_state1 = New Hampshire | running_mate1 = William R. King | electoral_vote1 = 4 | popular_vote1 = 17,763 | percentage1 = 50.23% | image2 = | nominee2 = Winfield Scott | party2 = Whig Party (United States) | home_state2 = New Jersey | running_mate2 = William A. Graham | electoral_vote2 = 0 | popular_vote2 = 15,856 | percentage2 = 44.84% | title = President | before_election = Millard Fillmore | before_party = Whig Party (United States) | after_election = Franklin Pierce | after_party = Democratic Party (United States) }}{{ElectionsIA}} The 1852 United States presidential election in Iowa took place on November 2, 1852, as part of the 1852 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for President and Vice President. Iowa voted for the Democratic candidate, Franklin Pierce, over Whig candidate Winfield Scott. Pierce won Iowa by a margin of 5.39%. Results{{Election box runningmate begin | title=United States presidential election in Iowa, 1852[1][2]}}|party = Democratic Party (United States) |candidate = Franklin Pierce |homestate = New Hampshire |vp_name = William R. King |vp_state = Alabama |votes = 17,763 |percentage = 50.23% |ev = 4 |evprct = 100.00% }} |party = Whig Party (United States) |candidate = Winfield Scott |homestate = New Jersey |vp_name = William A. Graham |vp_state = North Carolina |votes = 15,856 |percentage = 44.84% |ev = 0 |evprct = 0.00% }} |party = Free Soil Party |candidate = John P. Hale |homestate = New Hampshire |vp_name = George W. Julian |vp_state = Indiana |votes = 1,606 |percentage = 4.54% |ev = 0 |evprct = 0.00% }}{{Election box US candidate | party = | candidate = Write-in (other) | vp_name = N/A | votes = 139 | percentage = 0.39% |ev = 0 |evprct = 0.00% }}{{Election runningmate box total| |votes = 35,364 |percentage = 100.00% |ev = 4 |evprct = 100.00% }}{{Election box end}} References1. ^{{cite web|title=1852 Presidential General Election Results - Iowa|url=https://uselectionatlas.org/RESULTS/state.php?year=1852&fips=19&f=0&off=0&elect=0|publisher=U.S. Election Atlas|accessdate=1 December 2017}} {{State Results of the 1852 U.S. presidential election}}{{Iowa-election-stub}}2. ^{{cite web|title=1852 Presidential Election|url=http://www.presidency.ucsb.edu/showelection.php?year=1852|work=The American Presidency Project|publisher=University of California Santa Barbara|accessdate=1 December 2017}} 3 : 1852 United States presidential election by state|United States presidential elections in Iowa|1852 Iowa elections |
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