| 词条 | 2018 Challenger Banque Nationale de Granby – Men's Doubles |
| 释义 |
| champ = {{flagicon|USA}} Alex Lawson {{flagicon|CHN}} Li Zhe | runner = {{flagicon|USA}} JC Aragone {{flagicon|GBR}} Liam Broady | score = 7–6(7–2), 6–3 | edition = | main_name = Challenger de Granby }}{{main article|2018 Challenger Banque Nationale de Granby}} Joe Salisbury and Jackson Withrow were the defending champions but chose not to defend their title. Alex Lawson and Li Zhe won the title after defeating JC Aragone and Liam Broady 7–6(7–2), 6–3 in the final. Seeds{{columns-list|colwidth=30em|
}} Draw{{Draw key}}{{16TeamBracket-Compact-Tennis3-Byes| RD1=First Round | RD2=Quarterfinals | RD3=Semifinals | RD4=Final | RD1-seed03= | RD1-team03={{flagicon|CAN}} F Dancevic {{flagicon|CAN}} P Polansky | RD1-score03-1=6 | RD1-score03-2=63 | RD1-score03-3=[10] | RD1-seed04=WC | RD1-team04={{flagicon|CAN}} Taha Baadi {{flagicon|CAN}} Justin Boulais | RD1-score04-1=3 | RD1-score04-2=77 | RD1-score04-3=[6] | RD1-seed05=4 | RD1-team05={{flagicon|USA}} JC Aragone {{flagicon|GBR}} L Broady | RD1-score05-1=4 | RD1-score05-2=6 | RD1-score05-3=[11] | RD1-seed06= | RD1-team06={{flagicon|JPN}} Shintaro Imai {{flagicon|JPN}} K Uchida | RD1-score06-1=6 | RD1-score06-2=4 | RD1-score06-3=[9] | RD1-seed07= | RD1-team07={{flagicon|CAN}} Alexis Galarneau {{flagicon|CAN}} Benjamin Sigouin | RD1-score07-1=w/o | RD1-score07-2= | RD1-score07-3= | RD1-seed08= | RD1-team08={{flagicon|USA}} T Fawcett {{flagicon|USA}} Tyler Lu | RD1-score08-1= | RD1-score08-2= | RD1-score08-3= | RD1-seed09= | RD1-team09={{flagicon|GBR}} Luke Johnson {{flagicon|BRA}} João Menezes | RD1-score09-1=6 | RD1-score09-2=3 | RD1-score09-3=[10] | RD1-seed10=WC | RD1-team10={{flagicon|CAN}} JM Lin {{flagicon|CAN}} Nicaise Muamba | RD1-score10-1=4 | RD1-score10-2=6 | RD1-score10-3=[7] | RD1-seed11=WC | RD1-team11={{flagicon|CAN}} Washi Gervais {{flagicon|CAN}} Kelsey Stevenson | RD1-score11-1=4 | RD1-score11-2=3 | RD1-score11-3= | RD1-seed12=3 | RD1-team12={{flagicon|USA}} A Lawson {{flagicon|CHN}} Z Li | RD1-score12-1=6 | RD1-score12-2=6 | RD1-score12-3= | RD1-seed13= | RD1-team13={{flagicon|CAN}} Pavel Krainik {{flagicon|CAN}} Samuel Monette | RD1-score13-1=4 | RD1-score13-2=65 | RD1-score13-3= | RD1-seed14= | RD1-team14={{flagicon|BEL}} J De Loore {{flagicon|SVK}} N Gombos | RD1-score14-1=6 | RD1-score14-2=77 | RD1-score14-3= | RD1-seed15= | RD1-team15={{flagicon|AUS}} J Frawley {{flagicon|AUS}} Jacob Grills | RD1-score15-1=6 | RD1-score15-2=6 | RD1-score15-3= | RD1-seed16=2 | RD1-team16={{flagicon|AUS}} B Mousley {{flagicon|AUT}} M Neuchrist | RD1-score16-1=2 | RD1-score16-2=3 | RD1-score16-3= | RD2-seed01=1 | RD2-team01={{flagicon|AUS}} M Reid {{flagicon|JPN}} Y Uchiyama | RD2-score01-1=6 | RD2-score01-2=3 | RD2-score01-3=[10] | RD2-seed02= | RD2-team02={{flagicon|CAN}} F Dancevic {{flagicon|CAN}} P Polansky | RD2-score02-1=3 | RD2-score02-2=6 | RD2-score02-3=[7] | RD2-seed03=4 | RD2-team03={{flagicon|USA}} JC Aragone {{flagicon|GBR}} L Broady | RD2-score03-1=w/o | RD2-score03-2= | RD2-score03-3= | RD2-seed04= | RD2-team04={{flagicon|CAN}} A Galarneau {{flagicon|CAN}} B Sigouin | RD2-score04-1= | RD2-score04-2= | RD2-score04-3= | RD2-seed05= | RD2-team05={{flagicon|GBR}} L Johnson {{flagicon|BRA}} J Menezes | RD2-score05-1=79 | RD2-score05-2=1 | RD2-score05-3=[9] | RD2-seed06=3 | RD2-team06={{flagicon|USA}} A Lawson {{flagicon|CHN}} Z Li | RD2-score06-1=67 | RD2-score06-2=6 | RD2-score06-3=[11] | RD2-seed07= | RD2-team07={{flagicon|BEL}} J De Loore {{flagicon|SVK}} N Gombos | RD2-score07-1=6 | RD2-score07-2=79 | RD2-score07-3= | RD2-seed08= | RD2-team08={{flagicon|AUS}} J Frawley {{flagicon|AUS}} J Grills | RD2-score08-1=1 | RD2-score08-2=67 | RD2-score08-3= | RD3-seed01=1 | RD3-team01={{flagicon|AUS}} M Reid {{flagicon|JPN}} Y Uchiyama | RD3-score01-1=3 | RD3-score01-2=6 | RD3-score01-3=[4] | RD3-seed02=4 | RD3-team02={{flagicon|USA}} JC Aragone {{flagicon|GBR}} L Broady | RD3-score02-1=6 | RD3-score02-2=3 | RD3-score02-3=[10] | RD3-seed03=3 | RD3-team03={{flagicon|USA}} A Lawson {{flagicon|CHN}} Z Li | RD3-score03-1=6 | RD3-score03-2=4 | RD3-score03-3=[10] | RD3-seed04= | RD3-team04={{flagicon|BEL}} J De Loore {{flagicon|SVK}} N Gombos | RD3-score04-1=2 | RD3-score04-2=6 | RD3-score04-3=[6] | RD4-seed01=4 | RD4-team01={{flagicon|USA}} JC Aragone {{flagicon|GBR}} L Broady | RD4-score01-1=62 | RD4-score01-2=3 | RD4-score01-3= | RD4-seed02=3 | RD4-team02={{flagicon|USA}} A Lawson {{flagicon|CHN}} Z Li | RD4-score02-1=77 | RD4-score02-2=6 | RD4-score02-3= }} References
2 : 2018 ATP Challenger Tour|Challenger de Granby |
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