词条 | Module:Calendar date/Recurring |
释义 | --[[ Calculates the Gregorian date of a recurring holiday that varies year-to-year, but follows the rule "Nth [day of week] of [month]" "month" = month number (1 to 12) "weeknumber" = number of week (1 to 4, or -1 to mean "last") "dayofweek" = number that represents the day of the week, where 1 = Sunday and 7 = Saturday "year" = Gregorian calendar year ]] require('Module:No globals') local p = {} function p.calculate(frame) local args = frame.args local ONE_DAY = 86400 -- number of seconds in one day local year = tonumber(args.year) local month = tonumber(args.month) local weeknumber = tonumber(args.weeknumber) local dayofweek = tonumber(args.dayofweek) local date = os.time{year=year, month=month, day=1} local dateparts = os.date("*t", date)
if weeknumber > 0 then -- find the first [dayofweek] of this month while dateparts["wday"] ~= dayofweek do date = date + ONE_DAY dateparts = os.date("*t", date) end -- add the correct number of weeks if weeknumber > 1 then date = date + ((weeknumber - 1) * (7 * ONE_DAY)) end else -- find the first day of the next month while dateparts["month"] == month do date = date + ONE_DAY dateparts = os.date("*t", date) end -- go back one day to get the last day of the month we want date = date - ONE_DAY dateparts = os.date("*t", date) -- go backwards until we find the right day of week while dateparts["wday"] ~= dayofweek do date = date - ONE_DAY dateparts = os.date("*t", date) end end local result = os.date("%Y-%m-%d", date) return result end return p |
随便看 |
|
开放百科全书收录14589846条英语、德语、日语等多语种百科知识,基本涵盖了大多数领域的百科知识,是一部内容自由、开放的电子版国际百科全书。