词条 | Sokołowo, Podlaskie Voivodeship |
释义 |
| name = Sokołowo | settlement_type = Village | total_type = | image_flag = | image_shield = | image_map = | subdivision_type = Country | subdivision_name = {{POL}} | subdivision_type1 = Voivodeship | subdivision_name1 = Podlaskie | subdivision_type2 = County | subdivision_name2 = Suwałki County | subdivision_type3 = Gmina | subdivision_name3 = Bakałarzewo |pushpin_map=Poland |coordinates = {{coord|54|7|N|22|47|E|region:PL|display=inline}} | elevation_m = | population_total = | website = }} Sokołowo {{IPAc-pl|s|o|k|o|'|ł|o|w|o}} is a village in the administrative district of Gmina Bakałarzewo, within Suwałki County, Podlaskie Voivodeship, in north-eastern Poland.[1] It lies approximately {{convert|10|km|mi|0}} east of Bakałarzewo, {{convert|11|km|mi|0|abbr=on}} west of Suwałki, and {{convert|114|km|mi|0|abbr=on}} north of the regional capital Białystok. References1. ^{{cite web|url=http://www.stat.gov.pl/broker/access/prefile/listPreFiles.jspa|title=Central Statistical Office (GUS) – TERYT (National Register of Territorial Land Apportionment Journal)|date=2008-06-01|language=Polish}} {{Gmina Bakałarzewo}}{{coord|54.1167|N|22.7833|E|region:PL_type:city_source:enwiki-GNS-gminamatcher|display=title}}{{DEFAULTSORT:Sokolowo, Podlaskie Voivodeship}}{{Suwałki-geo-stub}} 1 : Villages in Suwałki County |
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