| 词条 | Sękowice, Lubusz Voivodeship |
| 释义 |
| name = Sękowice | settlement_type = Village | total_type = | image_skyline = | image_caption = | image_flag = | image_shield = | image_map = | subdivision_type = Country | subdivision_name = {{flag icon|Poland}} Poland | subdivision_type1 = Voivodeship | subdivision_name1 = Lubusz | subdivision_type2 = County | subdivision_name2 = Krosno Odrzańskie | subdivision_type3 = Gmina | subdivision_name3 = Gmina Gubin |pushpin_map=Poland |coordinates = {{coord|51|55|N|14|43|E|region:PL|display=inline}} | elevation_m = | population_total = | website = }} Sękowice {{IPAc-pl|s|e|n|k|o|'|w|i|c|e}} ({{lang-de|Schenkendorf}}) is a village in the administrative district of Gmina Gubin, within Krosno Odrzańskie County, Lubusz Voivodeship, in western Poland, close to the German border.[1] It lies approximately {{convert|4|km|mi|0}} south of Gubin, {{convert|30|km|mi|0|abbr=on}} south-west of Krosno Odrzańskie, and {{convert|55|km|mi|0|abbr=on}} west of Zielona Góra. Before 1945 the area was part of Germany (see Territorial changes of Poland after World War II). References1. ^{{cite web |url=http://www.stat.gov.pl/broker/access/prefile/listPreFiles.jspa |title=Central Statistical Office (GUS) – TERYT (National Register of Territorial Land Apportionment Journal) |date=2008-06-01 |language=Polish}} {{Gmina Gubin}}{{coord|51.9167|N|14.7167|E|region:PL_type:city_source:enwiki-GNS-gminamatcher|display=title}}{{DEFAULTSORT:Sekowice, Lubusz Voivodeship}}{{KrosnoOdrzańskie-geo-stub}} 1 : Villages in Krosno Odrzańskie County |
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