| 词条 | 1832 United States presidential election in Rhode Island | ||||||||||||||||||||||||||||||
| 释义 |
| election_name = United States presidential election in Rhode Island, 1832 | country = Rhode Island | type = presidential | ongoing = no | previous_election = United States presidential election in Rhode Island, 1828 | previous_year = 1828 | next_election = United States presidential election in Rhode Island, 1836 | next_year = 1836 | election_date = November 2 – December 5, 1832 | image1 = | nominee1 = Henry Clay | party1 = National Republican Party (United States) | home_state1 = Kentucky | running_mate1 = John Sergeant | electoral_vote1 = 4 | popular_vote1 = 2,810 | percentage1 = 56.93% | image2 = | nominee2 = Andrew Jackson | party2 = Democratic Party (United States) | home_state2 = Tennessee | running_mate2 = Martin Van Buren | electoral_vote2 = 0 | popular_vote2 = 2,126 | percentage2 = 43.07% | map_image = | map_size = | map_caption = }}{{ElectionsRI}} The 1832 United States presidential election in Rhode Island took place between November 2 and December 5, 1832, as part of the 1832 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for President and Vice President. Rhode Island voted for the National Republican candidate, Henry Clay, over the Democratic Party candidate, Andrew Jackson. Clay won Rhode Island by a margin of 13.86%. Results
References1. ^{{cite web|title=1832 Presidential General Election Results - Rhode Island|url=http://uselectionatlas.org/RESULTS/state.php?year=1832&f=1&off=0&elect=0&fips=44&submit=Retrieve|publisher=U.S. Election Atlas|accessdate=12 April 2013}} {{State Results of the 1832 U.S. presidential election}}{{RhodeIsland-election-stub}} 3 : 1832 United States presidential election by state|United States presidential elections in Rhode Island|1832 Rhode Island elections |
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