“1840 United States presidential election in Rhode Island”的意思、由来-开放百科全书

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1840 United States presidential election in Rhode Island

释义

Results
References

{{Main|United States presidential election, 1840}}{{Infobox Election
| election_name = United States presidential election in Rhode Island, 1840
| country = Rhode Island
| type = presidential
| ongoing = no
| previous_election = United States presidential election in Rhode Island, 1836
| previous_year = 1836
| next_election = United States presidential election in Rhode Island, 1844
| next_year = 1844
| election_date = October 30 - December 2, 1840
| image1 =
| nominee1 = William Henry Harrison
| party1 = Whig Party (United States)
| home_state1 = Ohio
| running_mate1 = John Tyler
| electoral_vote1 = 4
| popular_vote1 = 5,278
| percentage1 = 61.22%
| image2 =
| nominee2 = Martin Van Buren
| party2 = Democratic Party (United States)
| home_state2 = New York
| running_mate2 = none
| electoral_vote2 = 0
| popular_vote2 = 3,301
| percentage2 = 38.29%
| title = President
| before_election = Martin Van Buren
| before_party = Democratic Party (United States)
| before_color = FF3333
| after_election = William Henry Harrison
| after_party = Whig Party (United States)
| after_color = FF3333
}}{{ElectionsRI}}

The 1840 United States presidential election in Rhode Island took place between October 30 and December 2, 1840, as part of the 1840 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for President and Vice President.

Rhode Island voted for the Whig candidate, William Henry Harrison, over Democratic candidate Martin Van Buren. Harrison won Rhode Island by a margin of 22.93%.

With 61.22% of the popular vote, Rhode Island would be Harrison's third strongest state in the 1840 election after Kentucky and Vermont.^[1]

Results

{{Election box runningmate begin | title=United States presidential election in Rhode Island, 1840^[2]}}
|party = Whig Party (United States)
|candidate = William Henry Harrison
|homestate = Ohio
|vp_name = John Tyler
|vp_state = Virginia
|votes = 5,278
|percentage = 61.22%
|ev = 4
|evprct = 100.00%
}}
|party = Democratic Party (United States)
|candidate = Martin Van Buren
|homestate = New York
|vp_name = Richard M. Johnson
|vp_state = Kentucky
|votes = 3,301
|percentage = 38.29%
|ev = 0
|evprct = 0.00%
}}
|party = Liberty Party (1840s)
|candidate = James G. Birney
|homestate = New York
|vp_name = Thomas Earle
|vp_state = Pennsylvania
|votes = 42
|percentage = 0.49%
|ev = 0
|evprct = 0.00%
}}{{Election runningmate box total|
|votes = 8,621
|percentage = 100.00%
|ev = 4
|evprct = 100.00%
}}{{Election box end}}

References

1. ^{{cite web|url=https://uselectionatlas.org/RESULTS/stats.php?year=1840&f=1&off=0&elect=0|title=1840 Presidential Election Statistics|publisher=Dave Leip’s Atlas of U.S. Presidential Elections|date= |accessdate=2018-03-05}}
2. ^{{cite web|title=1840 Presidential General Election Results - Rhode Island|url=http://uselectionatlas.org/RESULTS/state.php?year=1840&f=1&off=0&elect=0&fips=44&submit=Retrieve|publisher=U.S. Election Atlas|accessdate=23 December 2013}}

3 : 1840 United States presidential election by state|United States presidential elections in Rhode Island|1840 Rhode Island elections

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