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词条 1996 United States presidential election in Iowa
释义

  1. Results

  2. References

  3. See also

{{Main|United States presidential election, 1996}}{{Infobox Election
| election_name = United States presidential election in Iowa, 1996
| country = Iowa
| type = presidential
| ongoing = no
| previous_election = United States presidential election in Iowa, 1992
| previous_year = 1992
| next_election = United States presidential election in Iowa, 2000
| next_year = 2000
| election_date = November 5, 1996
| image1 =
| nominee1 = Bill Clinton
| party1 = Democratic Party (United States)
| home_state1 = Arkansas
| running_mate1 = Al Gore
| electoral_vote1 = 7
| popular_vote1 = 620,258
| percentage1 = 50.26%
| image2 =
| nominee2 = Bob Dole
| party2 = Republican Party (United States)
| home_state2 = Kansas
| running_mate2 = Jack Kemp
| electoral_vote2 = 0
| popular_vote2 = 492,644
| percentage2 = 39.92%
| image3 =
| nominee3 = Ross Perot
| party3 = Reform Party of the United States of America
| home_state3 = Texas
| running_mate3 = James Campbell
| electoral_vote3 = 0
| popular_vote3 = 105,159
| percentage3 = 8.52%
| map_image = Iowa Presidential Election Results by County, 1996.svg
| map_size = 312px
| map_caption = County Results{{col-start}}{{col-2}}Clinton{{legend|#D4E6FF|30-40%}}{{legend|#b9d7ff|40-50%}}{{legend|#86b6f2|50-60%}}{{legend|#4389e3|60-70%}}{{col-2}}Dole{{legend|#f2b3be|40-50%}}{{legend|#e27f90|50-60%}}{{legend|#cc2f4a|60-70%}}{{legend|#d40000|70-80%}}{{col-end}}
| title = President
| before_election = Bill Clinton
| before_party = Democratic Party (United States)
| after_election = Bill Clinton
| after_party = Democratic Party (United States)
}}{{ElectionsIA}}

The 1996 United States presidential election in Iowa took place on November 7, 1996, as part of the 1996 United States presidential election. Voters chose 7 representatives, or electors to the Electoral College, who voted for president and vice president.

Iowa was won by Democratic incumbent President Bill Clinton over Republican Senator Bob Dole of Kansas, with Clinton winning 50.26% of the vote to Dole's 39.92%, a margin of 10.34%. The Reform Party candidate, billionaire businessman Ross Perot, finished in third, with 8.52% of the popular vote.[1]

Iowa is one of thirteen states where on the election ballot, James Campbell of California, Perot's former boss at IBM, was listed as a stand-in Vice-Presidential candidate.[1][3]

{{As of|2016|11|alt=As of the 2016 presidential election}}, this is the last time Iowa was decided by a double-digit margin. It is also the last time that Monona County, Appanoose County, Decatur County, Henry County, Butler County, Clay County, Dickinson County, Guthrie County, Keokuk County, Madison County, Lucas County, Wright County, Pocahontas County, Taylor County, Van Buren County, Wayne County, Dallas County, Washington County, Cherokee County, Hancock County, Calhoun County, Davis County, Monroe County, Adair County, and Ringgold County voted Democratic.

Results

United States presidential election in Iowa, 1996
PartyCandidateRunning mateVotesPercentageElectoral votes
Democratic Bill Clinton (incumbent) Al Gore620,25850.26%7
Republican Robert Dole Jack Kemp492,64439.92%0
Reform Ross Perot James Campbell105,1598.52%0
Green Ralph Nader Anne Goeke[1][5]6,5500.53%0
Natural Law Dr. John Hagelin Dr. V. Tompkins3,3490.27%0
Libertarian IA Harry Browne Jo Jorgensen2,3150.19%0
Taxpayer Howard Phillips Albion W. Knight Jr.[1][7]2,2290.18%0
No party Write-in1,2400.10%0
Socialist Workers James Harris Laura Garza3310.03%0
Totals1,234,075100.0%7
Voter Turnout (Voting age/Registered)58%/69%

References

[1][2][3][4]

See also

{{State Results of the 1996 U.S. presidential election}}{{United States elections, 1996}}

3 : 1996 United States presidential election by state|United States presidential elections in Iowa|1996 Iowa elections

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