| 词条 | 2014 ATP Challenger China International – Nanchang – Doubles |
| 释义 |
| edition = 1st | champ = {{flagicon|TPE}} Chen Ti {{flagicon|TPE}} Peng Hsien-yin | runner = {{flagicon|AUS}} Jordan Kerr {{flagicon|FRA}} Fabrice Martin | score = 6–2, 3–6, [12–10] | type = men }}{{main|2014 ATP Challenger China International – Nanchang}} This was the first edition of the tournament. Chen Ti and Peng Hsien-yin won the title, defeating Jordan Kerr and Fabrice Martin in the final, 6–2, 3–6, [12–10]. Seeds{{columns-list|colwidth=30em|
}} Draw{{Draw key}}Draw{{16TeamBracket-Compact-Tennis3| RD1=First Round | RD2=Quarterfinals | RD3=Semifinals | RD4=Final | RD1-seed01=1 | RD1-team01={{flagicon|TPE}} T Chen {{flagicon|TPE}} H-y Peng | RD1-score01-1=6 | RD1-score01-2=6 | RD1-score01-3= | RD1-seed02=WC | RD1-team02={{flagicon|CHN}} R Hua {{flagicon|CHN}} S Liu | RD1-score02-1=3 | RD1-score02-2=4 | RD1-score02-3= | RD1-seed03= | RD1-team03={{flagicon|CHN}} Y Bai {{flagicon|CHN}} D Wu | RD1-score03-1=6 | RD1-score03-2=6 | RD1-score03-3= | RD1-seed04= | RD1-team04={{flagicon|CHN}} Gong Peng-Xiang {{flagicon|CHN}} Gong Xiao | RD1-score04-1=2 | RD1-score04-2=2 | RD1-score04-3= | RD1-seed05=3 | RD1-team05={{flagicon|TPE}} H-h Lee {{flagicon|CHN}} Z Zhang | RD1-score05-1=6 | RD1-score05-2=7 | RD1-score05-3= | RD1-seed06= | RD1-team06={{nowrap|{{flagicon|THA}} N Kadchapanan}} {{flagicon|THA}} D Udomchoke | RD1-score06-1=3 | RD1-score06-2=5 | RD1-score06-3= | RD1-seed07= | RD1-team07={{flagicon|IND}} S Balaji {{flagicon|JPN}} Shuichi Sekiguchi | RD1-score07-1=6 | RD1-score07-2=6 | RD1-score07-3= | RD1-seed08=WC | RD1-team08={{flagicon|CHN}} Chen Long {{flagicon|CHN}} Wu Hao | RD1-score08-1=3 | RD1-score08-2=2 | RD1-score08-3= | RD1-seed09= | RD1-team09={{flagicon|CHN}} M Gong {{flagicon|JPN}} H Kondo | RD1-score09-1=65 | RD1-score09-2=77 | RD1-score09-3=[10] | RD1-seed10= | RD1-team10={{flagicon|USA}} N Meister {{flagicon|IND}} J Nedunchezhiyan | RD1-score10-1=77 | RD1-score10-2=62 | RD1-score10-3=[4] | RD1-seed11= | RD1-team11={{flagicon|KOR}} H Chung {{flagicon|KOR}} J-s Nam | RD1-score11-1=3 | RD1-score11-2=77 | RD1-score11-3=[10] | RD1-seed12=4 | RD1-team12={{flagicon|AUS}} R Agar {{flagicon|TPE}} L-c Huang | RD1-score12-1=6 | RD1-score12-2=65 | RD1-score12-3=[7] | RD1-seed13=WC | RD1-team13={{flagicon|CHN}} Y Ning {{flagicon|CHN}} A Wang | RD1-score13-1=3 | RD1-score13-2=2 | RD1-score13-3= | RD1-seed14= | RD1-team14={{flagicon|RUS}} D Matsukevich {{flagicon|RUS}} V Rudnev | RD1-score14-1=6 | RD1-score14-2=6 | RD1-score14-3= | RD1-seed15= | RD1-team15={{flagicon|JPN}} T Matsui {{flagicon|JPN}} G Soeda | RD1-score15-1=65 | RD1-score15-2=6 | RD1-score15-3=[6] | RD1-seed16=2 | RD1-team16={{flagicon|AUS}} J Kerr {{flagicon|FRA}} F Martin | RD1-score16-1=77 | RD1-score16-2=3 | RD1-score16-3=[10] | RD2-seed01=1 | RD2-team01={{flagicon|TPE}} T Chen {{flagicon|TPE}} H-y Peng | RD2-score01-1=77 | RD2-score01-2=6 | RD2-score01-3= | RD2-seed02= | RD2-team02={{flagicon|CHN}} Y Bai {{flagicon|CHN}} D Wu | RD2-score02-1=62 | RD2-score02-2=4 | RD2-score02-3= | RD2-seed03=3 | RD2-team03={{flagicon|TPE}} H-h Lee {{flagicon|CHN}} Z Zhang | RD2-score03-1=6 | RD2-score03-2=4 | RD2-score03-3=[10 | RD2-seed04= | RD2-team04={{flagicon|IND}} S Balaji {{flagicon|JPN}} S Sekiguchi | RD2-score04-1=2 | RD2-score04-2=6 | RD2-score04-3=[6] | RD2-seed05= | RD2-team05={{flagicon|CHN}} M Gong {{flagicon|JPN}} H Kondo | RD2-score05-1=2 | RD2-score05-2=7 | RD2-score05-3=[10] | RD2-seed06= | RD2-team06={{flagicon|KOR}} H Chung {{flagicon|KOR}} J-s Nam | RD2-score06-1=6 | RD2-score06-2=5 | RD2-score06-3=[7] | RD2-seed07= | RD2-team07={{flagicon|RUS}} D Matsukevich {{flagicon|RUS}} V Rudnev | RD2-score07-1=w/o | RD2-score07-2= | RD2-score07-3= | RD2-seed08=2 | RD2-team08={{flagicon|AUS}} J Kerr {{flagicon|FRA}} F Martin | RD2-score08-1= | RD2-score08-2= | RD2-score08-3= | RD3-seed01=1 | RD3-team01={{flagicon|TPE}} T Chen {{flagicon|TPE}} H-y Peng | RD3-score01-1=6 | RD3-score01-2=6 | RD3-score01-3= | RD3-seed02=3 | RD3-team02={{flagicon|TPE}} H-h Lee {{flagicon|CHN}} Z Zhang | RD3-score02-1=4 | RD3-score02-2=3 | RD3-score02-3= | RD3-seed03= | RD3-team03={{flagicon|CHN}} M Gong {{flagicon|JPN}} H Kondo | RD3-score03-1=3 | RD3-score03-2=4 | RD3-score03-3= | RD3-seed04=2 | RD3-team04={{flagicon|AUS}} J Kerr {{flagicon|FRA}} F Martin | RD3-score04-1=6 | RD3-score04-2=6 | RD3-score04-3= | RD4-seed01=1 | RD4-team01={{flagicon|TPE}} T Chen {{flagicon|TPE}} H-y Peng | RD4-score01-1=6 | RD4-score01-2=3 | RD4-score01-3=[12] | RD4-seed02=2 | RD4-team02={{flagicon|AUS}} J Kerr {{flagicon|FRA}} F Martin | RD4-score02-1=2 | RD4-score02-2=6 | RD4-score02-3=[10] }} References
2 : 2014 ATP Challenger Tour|ATP Challenger China International – Nanchang |
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