“2014 Challenger of Dallas – Doubles”的意思、由来-开放百科全书

词条

2014 Challenger of Dallas – Doubles

释义

Seeds
Draw
Draw
References

{{TennisEvents|2014|Challenger of Dallas|s
| champ = {{flagicon|AUS}} Samuel Groth
{{flagicon|AUS}} Chris Guccione
| runner = {{flagicon|USA}} Ryan Harrison
{{flagicon|BAH}} Mark Knowles
| score = 6–4, 6–2
| type = men
| after_name = RBC Tennis Championships of Dallas – Doubles
}}{{main|2014 Challenger of Dallas}}Alex Kuznetsov and Mischa Zverev were the defending champions but lost to Alex Bogomolov, Jr. and Jordan Kerr in the quarterfinals.

Top seeded Australians Samuel Groth and Chris Guccione won the title over wildcards Ryan Harrison and Mark Knowles.

Seeds

{{columns-list|colwidth=30em|

{{flagicon|AUS}} Samuel Groth / {{flagicon|AUS}} Chris Guccione (Champions)
{{flagicon|ITA}} Riccardo Ghedin / {{flagicon|ITA}} Alessandro Motti (First Round)
{{flagicon|USA}} Vahid Mirzadeh / {{flagicon|CAN}} Peter Polansky (First Round)
{{flagicon|USA}} Rajeev Ram / {{flagicon|USA}} Bobby Reynolds (First Round)

}}

Draw

{{16TeamBracket-Compact-Tennis3-Byes
| RD1=First Round
| RD2=Quarterfinals
| RD3=Semifinals
| RD4=Final
| RD1-seed01=1
| RD1-team01={{flagicon|AUS}} S Groth
{{flagicon|AUS}} C Guccione
| RD1-score01-1=6
| RD1-score01-2=6
| RD1-score01-3=
| RD1-seed02=WC
| RD1-team02={{flagicon|USA}} D Kosakowski
{{flagicon|USA}} N Meister
| RD1-score02-1=1
| RD1-score02-2=4
| RD1-score02-3=
| RD1-seed03=Q
| RD1-team03={{flagicon|USA}} A Halebian
{{flagicon|USA}} D Novikov
| RD1-score03-1=4
| RD1-score03-2=4
| RD1-score03-3=
| RD1-seed04=
| RD1-team04={{flagicon|USA}} K King
{{flagicon|COL}} J-C Spir
| RD1-score04-1=6
| RD1-score04-2=6
| RD1-score04-3=
| RD1-seed05=3
| RD1-team05={{flagicon|USA}} V Mirzadeh
{{flagicon|CAN}} P Polansky
| RD1-score05-1=3
| RD1-score05-2=2
| RD1-score05-3=
| RD1-seed06=LL
| RD1-team06={{flagicon|USA}} J Jung
{{flagicon|USA}} E King
| RD1-score06-1=6
| RD1-score06-2=6
| RD1-score06-3=
| RD1-seed07=
| RD1-team07={{nowrap|{{flagicon|DOM}} V Estrella Burgos}}
{{flagicon|DOM}} J Hernández
| RD1-score07-1=3
| RD1-score07-2=7
| RD1-score07-3=[9]
| RD1-seed08=PR
| RD1-team08={{flagicon|USA}} Alham El Effendi
{{flagicon|GBR}} D Walsh
| RD1-score08-1=6
| RD1-score08-2=5
| RD1-score08-3=[11]
| RD1-seed09=
| RD1-team09={{flagicon|IRL}} J McGee
{{flagicon|USA}} M Russell
| RD1-score09-1=6²
| RD1-score09-2=2
| RD1-score09-3=
| RD1-seed10=
| RD1-team10={{flagicon|RUS}} A Bogomolov, Jr.
{{flagicon|AUS}} J Kerr
| RD1-score10-1=7⁷
| RD1-score10-2=6
| RD1-score10-3=
| RD1-seed11=
| RD1-team11={{flagicon|USA}} A Kuznetsov
{{flagicon|GER}} M Zverev
| RD1-score11-1=6
| RD1-score11-2=6
| RD1-score11-3=
| RD1-seed12=4
| RD1-team12={{flagicon|USA}} R Ram
{{flagicon|USA}} B Reynolds
| RD1-score12-1=4
| RD1-score12-2=4
| RD1-score12-3=
| RD1-seed13=WC
| RD1-team13={{flagicon|USA}} R Harrison
{{flagicon|BAH}} M Knowles
| RD1-score13-1=7⁷
| RD1-score13-2=6
| RD1-score13-3=
| RD1-seed14=
| RD1-team14={{flagicon|USA}} C Buchanan
{{flagicon|GER}} T Puetz
| RD1-score14-1=6²
| RD1-score14-2=0
| RD1-score14-3=
| RD1-seed15=WC
| RD1-team15={{flagicon|USA}} Neil Kenner
{{flagicon|USA}} Andrew McCarthy
| RD1-score15-1=6
| RD1-score15-2=6
| RD1-score15-3=
| RD1-seed16=2
| RD1-team16={{flagicon|ITA}} R Ghedin
{{flagicon|ITA}} A Motti
| RD1-score16-1=1
| RD1-score16-2=2
| RD1-score16-3=
| RD2-seed01=1
| RD2-team01={{flagicon|AUS}} S Groth
{{flagicon|AUS}} C Guccione
| RD2-score01-1=6
| RD2-score01-2=7⁷
| RD2-score01-3=
| RD2-seed02=
| RD2-team02={{flagicon|USA}} K King
{{flagicon|COL}} J-C Spir
| RD2-score02-1=4
| RD2-score02-2=6⁴
| RD2-score02-3=
| RD2-seed03=LL
| RD2-team03={{flagicon|USA}} J Jung
{{flagicon|USA}} E King
| RD2-score03-1=6
| RD2-score03-2=3
| RD2-score03-3=[10]
| RD2-seed04=PR
| RD2-team04={{flagicon|USA}} A El Effendi
{{flagicon|GBR}} D Walsh
| RD2-score04-1=4
| RD2-score04-2=6
| RD2-score04-3=[6]
| RD2-seed05=
| RD2-team05={{flagicon|RUS}} A Bogomolov, Jr.
{{flagicon|AUS}} J Kerr
| RD2-score05-1=6
| RD2-score05-2=7
| RD2-score05-3=
| RD2-seed06=
| RD2-team06={{flagicon|USA}} A Kuznetsov
{{flagicon|GER}} M Zverev
| RD2-score06-1=2
| RD2-score06-2=5
| RD2-score06-3=
| RD2-seed07=WC
| RD2-team07={{flagicon|USA}} R Harrison
{{flagicon|BAH}} M Knowles
| RD2-score07-1=7
| RD2-score07-2=6
| RD2-score07-3=
| RD2-seed08=WC
| RD2-team08={{flagicon|USA}} N Kenner
{{flagicon|USA}} A McCarthy
| RD2-score08-1=5
| RD2-score08-2=1
| RD2-score08-3=
| RD3-seed01=1
| RD3-team01={{flagicon|AUS}} S Groth
{{flagicon|AUS}} C Guccione
| RD3-score01-1=6
| RD3-score01-2=7
| RD3-score01-3=
| RD3-seed02=LL
| RD3-team02={{flagicon|USA}} J Jung
{{flagicon|USA}} E King
| RD3-score02-1=2
| RD3-score02-2=5
| RD3-score02-3=
| RD3-seed03=
| RD3-team03={{flagicon|RUS}} A Bogomolov, Jr.
{{flagicon|AUS}} J Kerr
| RD3-score03-1=4
| RD3-score03-2=6
| RD3-score03-3=[9]
| RD3-seed04=WC
| RD3-team04={{flagicon|USA}} R Harrison
{{flagicon|BAH}} M Knowles
| RD3-score04-1=6
| RD3-score04-2=4
| RD3-score04-3=[11]
| RD4-seed01=1
| RD4-team01={{flagicon|AUS}} S Groth
{{flagicon|AUS}} C Guccione
| RD4-score01-1=6
| RD4-score01-2=6
| RD4-score01-3=
| RD4-seed02=WC
| RD4-team02={{flagicon|USA}} R Harrison
{{flagicon|BAH}} M Knowles
| RD4-score02-1=4
| RD4-score02-2=2
| RD4-score02-3=
}}

References

Main Draw

2 : 2014 ATP Challenger Tour|Challenger of Dallas

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